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To check for divisibility by 9 sum the digits of the number and if this sum is divisible by 9 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 9 so 32643 is divisible by 9.

As 9 = 3 × 3, any number divisible by 9 is also divisible by 3, thus as 32643 is divisible by 9 it is also divisible by 3.

However, for completeness: to check for divisibility by 3 sum the digits of the number and if this sum is divisible by 3 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 3 so 32643 is divisible by 3.

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Q: Is 32643 divisible by both 3 and 9?

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Yes it is... If you add the digits of ANY number together - and the result can be divided exactly by 3 or 9 - then the original number will also divide by 3 or 9. Since the digits of this number add together to make 18 - then 32643 will also divide by 3 or 9.

9 is divisible by both 3 and 9

378 is divisible by both 3 and 9 with no remainders

36360 is a 5 digit number that is divisible by both 3 and 9.

It is because 186426 = 3*62142 and 186426 = 9*20714.

Every number is divisible by any non-zero number. Furthermore, 4770 is evenly divisible by both 3 and 9.

Every number is divisible by any non-zero number. Furthermore, 405 is evenly divisible by both 3 and 9.

Both.

3 and 9. 93 has a digit sum of 12, initially, which is divisible by 3, but not by 9. So 93 is divisible by 3, but not by 9. 99 has a digit sum of 18, initially, which is divisible by 3 and 9. So 99 is divisible by both 3 and 9.

Yes, both.

Yes to both.

All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.

1, 2 and 3

3720 is even, so it is divisible by 2. The digits in 3720 add up to a multiple of 3, so it is divisible by 3. The units digit in 3720 is 0, so it is divisible by both 5 and 10. 3720 is divisible by both 2 and 3, so it is divisible by 6. The digits of 3720 do not add up to a multiple of 9, so it is NOT divisible by 9. Remember these tricks. Super useful. :)

It can be divided by 3 as in 12345/3=4115, but not 9 as in 12345/9=1371.6666666666666.

Neither, actually.

Yes but not evenly

no both are divisible by 3

Your question is impossible to answer. Any number that is divisible by both 2 and 5 will also be divisible by 10. 30 and 60 are not divisible by 9.

None, because 9 is divisible by 3.

Because 3 and 9 are both divisible by 3, we can simplify this fraction into 1/3.

Yes, both are divisible by 3, = 39/18, both are also divisible by 9, = 13/6

All numbers divisible by 9 are divisible by 3; since 9 = 3 x 3 all multiples of 9 are also multiples of 3. However, all numbers divisible by 3 are not divisible by 9, eg 6 = 2 x 3 but 6 is not divisible by 9 (since 6 is not a multiple of 9) - it only takes one counter example to disprove a theory.

Three is divisible by 3 and 9.